comparing and defining strings in C -

i looked @ other answers, not able find answer.
want compare last character of string literal "%".

  strcpy(ch, fname[strlen(fname) - 1]);   printf("%d\n", strcmp(ch, "%")); 

i want compile cl command line compiler (microsoft), , warnings:

cbx_test1.c(43) : warning c4047: 'function' : 'const char *' differs in levels of indirection 'char' cbx_test1.c(43) : warning c4024: 'strcpy' : different types formal , actual parameter 2 

there wrong code, that's obvious. what?

first need consider strings in c, sequences of non-nul bytes followed nul byte, trying copy character strcpy() meant copy strings, that's why compiler complaining.

you can simple assignment, i.e.

char   ch; size_t length;  length = strlen(fname); ch     = fname[length - 1]; 

and can compare ch '%' character constant this

printf("%d\n", (ch == '%')); 

note single quotes, wanted possible though not necessary, this

char   ch[2]; size_t length;  length = strlen(fname);  strcpy(ch, &fname[length - 1]); printf("%d\n", strcmp(ch, "%")); 

notice two characters allocated "%" become string since requires terminating nul byte, %\0, don't need explicitly specify when use string literal "%" since it's implied.

you use memcmp() not necessary in case, think it's interesting mention strcmp() not way compare 2 strings in c, could¹

char   ch[1]; size_t length;  length = strlen(fname); ch[0]  = fname[length - 1];  printf("%d\n", memcmp(ch, fname + length - 1, 1)); 

notice in case terminating '\0' not required because instructing memcmpt() compare 1 byte.

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¹_{note fname + length - 1 equivalent &fname[length - 1]}