Passing parameters - Shell -


suppose have folder(f1) below files,

wireport_614.log wireport_615.log boecms12.log boecms13.log

now have code below fetch unique parameters above files using script,

$home/findexceptions_bo.pl < .log >> $home/exceptions.log

so need pass .log files f1(n number of files) 1 one , run above script below,

$./script.sh $home/findexceptions_bo.pl < wireport_614.log >> $home/exceptions.log $home/findexceptions_bo.pl < wireport_615.log >> $home/exceptions.log

please let me know how pass , execute script.

loop on files 1 @ time:

for file in /folder/*.log;     $home/findexceptions_bo.pl < "$file" >> $home/exceptions.log done

or concatenate of log files , process them @ once, if that'll work you.

cat /folder/*.log | $home/findexceptions_bo.pl >> $home/exceptions.log

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