python - Counting all nodes of all paths from root to leaves -


if given tree nodes integers: 1 ~ 10, , branching factor of 3 nodes, how can write function traverses through tree counting root leaves every paths

so example, let's needs return this:

{1: 1, 2: 5}

i've tried helper function:

def tree_lengths(t):     temp = []     in t.children:         temp.append(1)         temp += [e + 1 e in tree_lengths(i)]     return temp

there many errors code. one, leaves behind imprints of every visited node in traversal in returning list - it's difficult figure out ones values need list. another, if tree large, not leave behind imprints of root , earlier nodes in path prior reaching line "for in t.children". needs first: duplicate paths root leaves; second: return list exclusively final number of each path count.

please help! difficult.

i'm not sure trying do, you'll need define recursive function takes node (the head of tree or subtree) , integer (the number of children you've traversed far), , maybe list of each visited node far. if node has no children, you've reached leaf , can print out whatever info need. otherwise, each child, call recursive function again new parameters (+1 count, child node head node, etc).


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