Why 'segmentation fault' occurs in the following C code -

$hoho   b  abcd  $hoho | lala  segmentation fault 

lala.c -->

#include<stdio.h> int main(int argc, char* argv){  printf("%s\n", argv[1]);  ... } 

then, how can use std_input a, b , abcd

1. your main() has wrong signature. it's not

   int main(int argc, char* argv) 

   it's

   int main(int argc, char **argv) 

   or equivalently

   int main(int argc, char *argv[]) 

2. you trying print char "%s" specifier, printf() function tries read string , interprets char value address because it's expecting char pointer, leads undefined behavior¹ , hence problem.

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¹_{please read link posted @souravghosh answer advice.}