c++ - Passing a temporary as a reference -

i trying understand copy , swap idiom through post. answer posted has following code in it

class dumb_array { public:     // ...      friend void swap(dumb_array& first, dumb_array& second) // nothrow     {         // enable adl (not necessary in our case, practice)         using std::swap;           // swapping members of 2 classes,         // 2 classes swapped         swap(first.msize, second.msize);          swap(first.marray, second.marray);     }      // move constructor     dumb_array(dumb_array&& other)         : dumb_array() // initialize via default constructor, c++11     {         swap(*this, other); //<------question statement     }      // ... }; 

i noticed author used statement

swap(*this, other); 

other temporary or rvalue being passed reference method swap. not sure if pass rvalue reference. in order test tried doing following not work until convert parameter const reference

void myfunct(std::string& f) {     std::cout << "hello"; }  int main()  {    myfunct(std::string("dsdsd")); } 

my question how can other being temporary passed reference in swap(*this, other); while myfunct(std::string("dsdsd")); cant passed reference.

the constructor takes rvalue reference, other lvalue (it has name).