if statement - Python: loop in elif condition -

i'm running python 3.

is possible put loop in condition elif? here's basic idea i'm trying achieve. number of items in list not constant.

if some_condition:     elif [ x.method() x in list ]:     x else:     else 

now, comes mind:

if some_condition:     x in list:     if x.method():         x         break 

but i'm trying avoid running if statements, there's lot of stuff going on in them. , in elif part , not in else.

edit / more clarification:

it seems need any( x.method() x in list ) reference x can use x if condition true.

here's whole concept i'm trying again:

if condition:     elif list[0].method():     list[0] elif list[1].method():     list[1] ... elif list[n].method():     list[n] else:     

where method() method returns true or false, , n size of list , not constant.

i don't think want -- have entirely in elif -- possible. you'd have evaluate whether there any such value in list, , bind x in condition. far know, not possible in python's syntax. you can not assignment in condition, , while loop variable in list comprehension can "leak" outside scope, same not true generator.

>>> if any(x x in range(10) if x >= 5): ...     print x nameerror: name 'x' not defined >>> if any([x x in range(10) if x >= 5]): ...     print x 9 

in second case (list), have reference x, last value entire list, , in first case (generator), x can not resolved @ all.

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instead, here's variant, using generator expression combine for if, , adding else for enumate final else clause.

if some_condition:     print "do this" else:     x in (x x in lst if foo(x)):         print "do to", x         break     else:         print "do else"