c++ - Can't get my pointers to send a reference to the array -

#include<stdio.h> #include<stdlib.h>  int* getevennumbers(int arr[], int n) {     int i, k = 0 , a[50], p;     (i = 0; < n; i++)        {            if (arr[i] % 2 == 0)             {               arr[k]=arr[i];                k++;             }        }        return arr[k]; }    int main () { int i, arr[5000000], n, a[500000], k, *p;      printf("\nenter desired length of array:\n\n");     scanf("%d", &n);      (i = 0; < n; i++)         arr[i]=  rand();      getevennumbers (arr, n);          printf("\n\neven numbers in array follows:\n\n");     (i = 0; < n; i++)         {         a[i]= *(p+i);       printf("\n[%d] = %d", (i+1), a[i]);         } } 

please know easy guys need figuring out how return pointer array without values of array getting deleted, can't use global variables , has function returns pointer pointing array

first of all, decrease size of arrays, don't need space. second of all, made

getevennumbers

function return int *, , not int. arr[k] not int *. don't why returning if nothing being assigned when call function. can change return type void.

void getevennumbers(int arr[], int n)

you never allocate memory p. can do

p = (int*) malloc(sizeof(int));

and since never allocated memory p, following line of code

a[i]= *(p+i);

is assigning a[i] random address. should try rewrite program. there lot of errors in program didn't correct. go on google finding numbers in array program or similar , @ code of examples.

edit:

i found code examples use. hope helps!

stackoverflow

sanfoundry.com