regex - Using grep, how can I extract every number from a blob of text? -
unlike previous question, want on commandline (just grep).
how can grep every number text file , display results?
sample text:
this sentence 1 number, while number 2 appears here, too.
i expect able extract "1" , "2" text (my actual text substantially longer, of course).
i think want this,
$ echo 'this sentence 1 number, while number 2 appears here, too.' | grep -o '[0-9]\+' 1 2
since basic sed uses bre
(basic regular expression), need escape +
symbol repeat previous character 1 or more times.
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