sql - Mysql search if last 3 records exist with same order -


i have table column of numbers

35 24 7 8 11 35 9 11 6 6 23 23 34 5 14 31 26 2 16 0 6 23 23

i want check if last 3 records

6 23 23

exist in previous records same order , result next number.

in example : 

6 23 23

exist same order , result must : 34

assuming numbers ordered auto_incremented column named id query should work:

select numbers  vista  id = (     select b.id + 3 (       select t1.id, t1.numbers t1val, t2.numbers t2val, t3.numbers t3val        vista t1        join vista t2 on t1.id = t2.id-1        join vista t3 on t1.id = t3.id-2        t1.id = (select max(id) - 2 vista)     )     join (       select t1.id, t1.numbers t1val, t2.numbers t2val, t3.numbers t3val        vista t1        join vista t2 on t1.id = t2.id-1        join vista t3 on t1.id = t3.id-2        t1.id < (select max(id) - 2 vista)     ) b    on a.t1val = b.t1val    , a.t2val = b.t2val    , a.t3val = b.t3val    , a.id <> b.id )  order id limit 1;

if id column doesn't contain sequence can generate 1 appropriate row numbering query.

sample sql fiddle


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