regex - How to find which group is matched in NSRegularExpression -

i have regex statement multiple capture groups separated | operator. how can find out capture group matched? way can think of -for example- counting number of characters if matched.

var string = "1234567897" var pattern = "(^\\d{9}$)|(^\\d{10}$)|(^\\d{13}$)|(^[a-za-z]{2}\\d{9}[a-za-z]{2}$)"  var myregex = nsregularexpression(pattern: pattern, options: nil, error: nil)!  if let mymatch = myregex.firstmatchinstring(string, options: nil,     range: nsrange(location: 0, length: string.utf16count)) {         println((string nsstring).substringwithrange(mymatch.rangeatindex(0)))  } 

i wrote code worked example. sure can written better way works now.

swift 2.3

var string = "123456789" var pattern = "(^\\d{9}$)|(^\\d{10}$)|(^\\d{13}$)|(^[a-za-z]{2}\\d{9}[ww]{2}$)"  var myregex = try! nsregularexpression(pattern: pattern, options: [])  if let mymatch = myregex.firstmatchinstring(string, options: nsmatchingoptions.init(rawvalue: 0), range: nsrange(location: 0, length: string.utf16.count)) {     var matchedgroup = 0      var in 1..<mymatch.numberofranges {         if mymatch.rangeatindex(i).length != 0 {             matchedgroup =             break         }      }     print(matchedgroup)     print((string nsstring).substringwithrange(mymatch.rangeatindex(0))) //whatever range want print  } 

swift 3

var string = "123456789" var pattern = "(^\\d{9}$)|(^\\d{10}$)|(^\\d{13}$)|(^[a-za-z]{2}\\d{9}[ww]{2}$)"  var myregex = try! nsregularexpression(pattern: pattern, options: [])  if let mymatch = myregex.firstmatch(in: string, options: nsregularexpression.matchingoptions.init(rawvalue: 0), range: nsrange(location: 0, length: string.utf16.count)) {     var matchedgroup = 0      var in 1..<mymatch.numberofranges {         if mymatch.rangeat(i).length != 0 {             matchedgroup =             break         }      }     print(matchedgroup)     print((string nsstring).substring(with: mymatch.rangeat(0))) //whatever range want print  }