shell - How do I split a string on a delimiter in Bash? -

i have string stored in variable:

in="bla@some.com;john@home.com" 

now split strings ; delimiter have:

addr1="bla@some.com" addr2="john@home.com" 

i don't need addr1 , addr2 variables. if elements of array that's better.

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after suggestions answers below, ended following after:

#!/usr/bin/env bash  in="bla@some.com;john@home.com"  mails=$(echo $in | tr ";" "\n")  addr in $mails     echo "> [$addr]" done 

output:

> [bla@some.com] > [john@home.com] 

there solution involving setting internal_field_separator (ifs) ;. not sure happened answer, how reset ifs default?

re: ifs solution, tried , works, keep old ifs , restore it:

in="bla@some.com;john@home.com"  oifs=$ifs ifs=';' mails2=$in x in $mails2     echo "> [$x]" done  ifs=$oifs 

btw, when tried

mails2=($in) 

i got first string when printing in loop, without brackets around $in works.

you can set internal field separator (ifs) variable, , let parse array. when happens in command, assignment ifs takes place single command's environment (to read ). parses input according ifs variable value array, can iterate over.

ifs=';' read -ra addr <<< "$in" in "${addr[@]}";     # process "$i" done 

it parse 1 line of items separated ;, pushing array. stuff processing whole of $in, each time 1 line of input separated ;:

 while ifs=';' read -ra addr;       in "${addr[@]}";           # process "$i"       done  done <<< "$in"